you sampled a poupulation in which you know the percentage if the homozygous recesive genotype is 36%. using that 36%

Question

you have sampled a population in which you know that the percentage if the homozygous recessive genotype(aa)  is 36%. using that 36% calculate the following:  The frequency of the "aa" genotype, the frequency of the "a" , The frequency of the "A" allele, the frequencies of the genotypes "aa" the frequencies of the genotype "aa",  the frequencies of the two possible phenotypes if "A" is completely dominate "a"?

Answer 1

In the Hardy-Weinberg law, the proportion of recessive individuals in the population is represented by q^2. So, in this problem, q^ = 0.36. From that, you can calculate q = 0.6. Then, since p+q = 1, p = 0.4.

Now, the proportion of homozygous dominant individuals is p^2 = 0.4^2 = 0.16, and the proportion of heterozygotes in the population is 2pq = 2(0.4)(0.6) = 0.48.