The cross would be something like AaBb X AaBb. So, when these are crossed, 9/16 of the offspring will be A_B_ and will show the dominant phenotype for both traits. 3/16 will be A_bb and will show the first dominant trait but will be recessive for the second. 3/16 will be aaB_ and will be dominant for the second trait, but recessive for the first. Finally 1/16 will be aabb and will be recessive for both traits.